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    Jaggers named Big Ten Wrestler of the Week

    COLUMBUS, Ohio -- J Jaggers, a junior on the seventh-ranked Ohio State wrestling team, was named Big Ten Wrestler of the Week the conference announced Wednesday. This is Jaggers' first-career weekly honor.

    A 2007 All-American at 141 pounds, Jaggers (16-5) lifted the Buckeyes to a 22-19 victory over No. 8 Penn State last Friday in St. John Arena. With the Buckeyes down three (19-16) with one bout remaining, Jaggers (Northfield, Ohio) pinned fifth-ranked Jake Strayer in 3:25 to seal the win. Ohio State trailed throughout the evening, but took its first and only lead for the win after Jaggers' pin.

    It was Jaggers' second victory of the season over Strayer as he also defeated the Nittany Lion, 6-4, at the National Duals Jan. 13. Strayer was No. 2 in the nation at the time.

    The win by Jaggers marked the sixth time this season he has beaten a Top 20 wrestler. Of his six wins over a ranked grappler, three have come via fall.

    Ohio State (14-3; 2-1 Big Ten) will hit the road for three-consecutive matches beginning Friday at 7 p.m. at Indiana. The Buckeyes then will face Purdue at 1 p.m. Sunday in West Lafayette, Ind. The three-match road swing concludes at 7 p.m. at Michigan State in East Lansing.

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